Possible to create BitX with invalid value (out of range) #8

This works correctly:

Bit3 b3 = 99;

I got the expected error: "Constant value '99' cannot be converted to a 'Bit3'"

but this passes:

Bit3 b3 = 98 + 1;

Admittedly is strange to use the '+' on a Bit... I don't if is possible to catch this error too or not...