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'filter' object has no attribute 'pop' #512
Description
In the export.py line 46
I'm getting the below error...
Traceback (most recent call last):
File "export.py", line 84, in <module>
main()
File "export.py", line 56, in main
view = views.pop()
AttributeError: 'filter' object has no attribute 'pop'I'm calling it as illustrated below:
python export.py --csv --file export1.csv `report_ID`Do i need to specify any further information?
Activity
andrewbcooper commentedon Jan 8, 2020
I had the same issue and found this on Stackoverflow. Are you using Python 3.x? If so, edit the code to be:
views = filter(lambda x: x.id == args.resource_id,
TSC.Pager(server.views.get))
views = list(views)
view = views.pop()
https://stackoverflow.com/questions/34820657/filter-object-has-no-attribute-pop
JoeyKwok commentedon Aug 18, 2020
Mine returns 'IndexError: pop from empty list', using python 3.6 corrected with list.
I am using view.id as report_ID. Am I using the correct one?
bcantoni commentedon Sep 1, 2020
Confirmed this is still a bug in the sample. There are 2 issues here:
jacalata commentedon Jun 7, 2022
The updated samples should cover this nicely.