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Parse error when passing keyword arguments after forwarding **args #2580
Description
def spam(x, y): pass
def ok(**kwargs) -> None:
spam(x=1, **kwargs) # OK
def err(**kwargs) -> None:
spam(**kwargs, x=1) # error: Parse error before "x"
I wouldn't think the order matters. The Python interpreter does not have an issue with it.
With --fast-parser I get error: "spam" gets multiple values for keyword argument "x" instead. Should I open a separate issue for this?
Activity
JukkaL commentedon Dec 15, 2016
We won't fix any parser issues that can be worked around by using
--fast-parser, since we hope to make that the default soon. The other problem may be new -- please go ahead and create a new issue for it.