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Incorrect behavior of inspect.signature(f).bind #87106
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slavkostrov commented
on Jan 16, 2021 slavkostrovmannequinMannequinAuthor>>> def foo(a, /, b=1, **kwargs): pass ... >>> foo(a=1) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: foo() missing 1 required positional argument: 'a' >>> inspect.signature(foo).bind(a=1) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "\Python\Python39\lib\inspect.py", line 3062, in bind return self._bind(args, kwargs) File "\Python\Python39\lib\inspect.py", line 2958, in _bind raise TypeError(msg) from None TypeError: 'a' parameter is positional only, but was passed as a keyword
There is a different behaviour between a simple function call and inspect.signature(foo).bind - different TypeError messages.
I think inspect should check for VARKEYWORDS before throwing an error and throw only if there are not.
In another case, inspect.signature(foo).bind gives a TypeError when no TypeError is even raised in the actual call:
>>> def foo(a=0, /, b=1, **kwargs): pass ... >>> foo(a=1) >>> inspect.signature(foo).bind(a=1) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/inspect.py", line 3037, in bind return self._bind(args, kwargs) File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/inspect.py", line 2933, in _bind raise TypeError(msg) from None TypeError: 'a' parameter is positional only, but was passed as a keyword
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on Jul 17, 2024
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inspect.signature.bindhandling of positional-only arguments with**kwargs#103404