add swarm plot

I can't find swarm plot in plotly, but can use this way to plot a swarm map:

import plotly.express as px
import numpy as np
import pandas as pd

np.random.seed(1)
y0 = np.random.randn(50) - 1

mm=pd.DataFrame({"org":y0})
tmp=[]
for k in y0:
    tmp.append(np.floor(k*10)/10)
mm["cut"]=tmp
cc=pd.DataFrame(columns=["x","y"])
width=0.08
for s in mm.groupby("cut"):
    # print(type(s))
    x=s[0]
    mp=s[1]
    ls=len(s[1])
    mid= int(ls/2)
    org= -mid
    if ls%2==0:
        org=org+0.5
        for i in range(ls):
            cc.loc[len(cc)]=[x,(i+org)*width]
        # for i in range(ls):
        #     if i == mid:
        #         org=org+1
        #     cc.loc[len(cc)]=[x,(i+org)*width]
    else:
        for i in range(ls):
            cc.loc[len(cc)]=[x,(i+org)*width]
  
# print(mm)
# print(cc)

fig = px.scatter(cc,x='x',y='y',range_y=[-2,2])
# fig=px.strip(cc,x='x',y='y',range_y=[-2,2])

fig.show()

this is a example for how to deal data and transform data for swarm

@suterberg

thanks @suterberg - have you posted this to our forums https://community.plotly.com/ as well? you may get a faster response there.

Would a version of this example -- with e.g. more comments, a static data set, and support for more than one category -- be welcome in the scatterplot documentation? Would that be an efficient way to largely address the concern?

Would a version of this example -- with e.g. more comments, a static data set, and support for more than one category -- be welcome in the scatterplot documentation? Would that be an efficient way to largely address the concern?

Needs 1-dimensional data
Classify data with an interval of 0.1
Aggregate data through groupby
Traverse aggregated data, add two-dimensional points based on the number of data, obtain two-dimensional data cc
Draw image

@suterberg

@suterberg Cool! To get a sense of where this might go, you could look at a couple examples of documentation pull requests that @SimaRaha and I have submitted: #4994 is most of the way through the review process and is pretty routine. #4983 is a bit atypical, but has some deep similarities to the swarm plot. For example, both #4983 and the swarm plot example above harness scatter to build a new graph type. Both would add documentation rather than adding a new function to the library. The changed files tabs on the pull requests show you exactly what we're submitting -- it's a combination of code like the above and terse commentary -- and the conversation tab shows the documentation expectations checklist; there's also a contributing guide here:
https://github.com/plotly/plotly.py/blob/main/CONTRIBUTING.md An easy way to start a documentation PRs is by clicking the "suggest an edit to this page" in the plotly documentation. We should likely get a reaction from @LiamConnors to #4983 in the coming weeks that will be instructive about whether and how to pursue swarmplot as a documentation pull request.

I hope that is helpful and apologize if some of that was obvious. Thank you for starting this constructive conversation!

@suterberg Cool! To get a sense of where this might go, you could look at a couple examples of documentation pull requests that @SimaRaha and I have submitted: #4994 is most of the way through the review process and is pretty routine. #4983 is a bit atypical, but has some deep similarities to the swarm plot. For example, both #4983 and the swarm plot example above harness scatter to build a new graph type. Both would add documentation rather than adding a new function to the library. The changed files tabs on the pull requests show you exactly what we're submitting -- it's a combination of code like the above and terse commentary -- and the conversation tab shows the documentation expectations checklist; there's also a contributing guide here: https://github.com/plotly/plotly.py/blob/main/CONTRIBUTING.md An easy way to start a documentation PRs is by clicking the "suggest an edit to this page" in the plotly documentation. We should likely get a reaction from @LiamConnors to #4983 in the coming weeks that will be instructive about whether and how to pursue swarmplot as a documentation pull request.

I hope that is helpful and apologize if some of that was obvious. Thank you for starting this constructive conversation!

import numpy as np
import pandas as pd
import plotly.express as px


def swarm(
    data_frame=None,
    pitch_x=0.1,
    pitch_y=0.1,
    point_size=16,
    range_x=None,
    range_y=None,
):
    if data_frame is None:
        np.random.seed(1)
        data_frame = pd.DataFrame({"org": np.random.randn(50) - 1})
    else:
        data_frame = pd.DataFrame({"org": data_frame})
    if range_x is None:
        range_x = [
            np.floor((data_frame["org"].min() - pitch_x) / pitch_x) * pitch_x,
            np.floor((data_frame["org"].max() + pitch_x) / pitch_x) * pitch_x,
        ]

    tmp = []
    for val in data_frame["org"]:
        tmp.append(np.floor(val / pitch_x) * pitch_x)
    data_frame["cut"] = tmp

    darw_date = pd.DataFrame(columns=["x", "y", "value"])

    for gp in data_frame.groupby("cut"):
        x = gp[0]
        nums = len(gp[1])
        mid = int(nums / 2)
        org = -mid

        values = gp[1]["org"].sort_values()
        values = values.to_list()

        if nums % 2 == 0:
            org = -mid + 0.5
            for i, val in enumerate(values):
                index = len(darw_date)
                darw_date.loc[index] = [x, (i + org) * pitch_y, val]
        else:
            for i, val in enumerate(values):
                index = len(darw_date)
                darw_date.loc[index] = [x, (i + org) * pitch_y, val]


    if range_y is None:
        range_y = [darw_date["y"].min() - pitch_y, darw_date["y"].max() + pitch_y]
    fig = px.scatter(
        darw_date,
        x="x",
        y="y",
        range_x=range_x,
        range_y=range_y,
        hover_data="value",
    )
    fig.update_traces(marker_size=point_size)
    fig.show()


if __name__ == "__main__":
    swarm(pitch_x=0.1, range_y=[-0.6, 0.6])

这个可能是你想要的，但是我认为没什么意义

I'm busy with some other things right now, but plan to either make code based on your examples into a documentation pull request or convince a collaborator to do so. I'll revise into something that makes sense to me and that is well commented, but will tag you on the PR -- so you should get an email about it -- and welcome your comments on it either in the pull request or here. If someone else beats me to it, that's terrific too. I plan to support multiple categories; I think I can pull much of what I need from #4983. Many thanks!

from decimal import ROUND_FLOOR, ROUND_HALF_DOWN, ROUND_HALF_UP, Decimal, getcontext
from math import pi
from typing import Literal

import numpy as np
import pandas as pd
import plotly.express as px

# 设置精度
getcontext().prec = 10


def swarm(
    data_frame=None,
    pitch_x=0.1,
    pitch_y=0.1,
    point_size=16,
    range_x=None,
    range_y=None,
    round_rule: Literal["floor", "hf_up", "hf_down"] = "hf_up",
):
    if data_frame is None:
        np.random.seed(1)
        data_frame = pd.DataFrame({"org": np.random.randn(50) - 1})
    else:
        print(data_frame)
        data_frame = pd.DataFrame({"org": data_frame})

    if range_x is None:
        range_x = [
            np.floor((data_frame["org"].min() - 2 * pitch_x) / pitch_x) * pitch_x,
            np.floor((data_frame["org"].max() + 2 * pitch_x) / pitch_x) * pitch_x,
        ]

    tmp = []
    rule = ROUND_HALF_UP
    match round_rule:
        case "floor":
            rule = ROUND_FLOOR
        case "hf_up":
            rule = ROUND_HALF_UP
        case "hf_down":
            rule = ROUND_HALF_DOWN

    for val in data_frame["org"]:
        a = Decimal(f"{val}")
        b = Decimal(f"{pitch_x}")
        tmp.append((a / b).quantize(Decimal("0"), rule) * b)
    data_frame["cut"] = tmp
    darw_date = pd.DataFrame(columns=["x", "y", "value"])

    for gp in data_frame.groupby("cut"):
        x = gp[0]
        nums = len(gp[1])
        mid = int(nums / 2)
        org = -mid

        values = gp[1]["org"].sort_values()
        values = values.to_list()

        if nums % 2 == 0:
            org = -mid + 0.5
            for i, val in enumerate(values):
                index = len(darw_date)
                darw_date.loc[index] = [x, (i + org) * pitch_y, val]
        else:
            for i, val in enumerate(values):
                index = len(darw_date)
                darw_date.loc[index] = [x, (i + org) * pitch_y, val]
    print(darw_date)

    if range_y is None:
        range_y = [darw_date["y"].min() - pitch_y, darw_date["y"].max() + pitch_y]
    fig = px.scatter(
        darw_date,
        x="x",
        y="y",
        range_x=range_x,
        range_y=range_y,
        hover_data="value",
    )
    fig.update_traces(
        marker_size=point_size,
        hovertemplate="<b>value</b>: %{customdata}",
    )
    fig.show()


if __name__ == "__main__":
    from sklearn.datasets import load_iris

    data = load_iris()
    feature_names = [
        "Sepal length",
        "Sepal width",
        "Petal length",
        "Petal width",
    ]
    X_df = pd.DataFrame(data.data, columns=feature_names)
    swarm(X_df["Sepal length"], pitch_x=0.2, pitch_y=0.05, range_y=[-0.8, 0.8])
    swarm(X_df["Sepal length"], pitch_x=0.1, pitch_y=0.03, range_y=[-0.4, 0.4])
    swarm(pitch_x=0.1, range_y=[-0.6, 0.6])

add swarm plot to the scatter documentation

I just proposed a change to the documentation, #5149, to show how to make a swarm plot. I started with the code above and made a bunch of changes to avoid icon collisions and simplify things. I welcome comments on how to make that code and documentation even better. Thank you for this good suggestion and interesting coding challenge.

I would certainly welcome an effort to convert something akin to #5149 into a px.swarmplot function, but also think documentation might be plenty. (#5149 is not my most performant code.)

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gvwilson commented on Mar 17, 2025

rl-utility-man commented on Apr 12, 2025

suterberg commented on Apr 12, 2025

rl-utility-man commented on Apr 13, 2025

suterberg commented on Apr 13, 2025

rl-utility-man commented on Apr 16, 2025

suterberg commented on Apr 18, 2025

rl-utility-man commented on Apr 20, 2025

rl-utility-man commented on Jun 3, 2025

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