ggplotly fails to convert geom_tile element with no fill aesthetic.

The ggplotly fails to convert geom_tile element with no fill aesthetic.

library(ggplot2)

set.seed(1503)

df <- data.frame(x = rep(1:3, 3),
                 y = rep(1:3, 3),
                 z = sample(c("A","B"), 9,replace = TRUE), 
                 stringsAsFactors = F)

p1 <- ggplot(df)+
  geom_tile(aes(x=x,y=y, fill="grey"), color = "black")

p2 <- ggplot(df)+
  geom_tile(aes(x=x,y=y),fill="grey", color = "black")

class(plotly::ggplotly(p1))
#> [1] "plotly"     "htmlwidget"
class(plotly::ggplotly(p2))
#> Error in `[.data.frame`(g, , c("fill_plotlyDomain", "fill")): undefined columns selected

Details:
looks like the code is breaking here
https://github.com/ropensci/plotly/blob/2cc296de6f77515003378a64b9fbdc93298ab45b/R/layers2traces.R#L849

Running into same issue. Does anyone have a fix?

Even more minimal example, showing how a missing fill aesthetic causes the issue. Maybe plotly should assume one, or fill invisibly if not provided? I.e. if no "fill" column exists in g then fill = "black", as ggplot does.

library(plotly)

df <- data.frame(x = rep(1:3, 3),
                 y = rep(1:3, 3),
                 z = sample(c("A","B"), 9,replace = TRUE))

p1 <- ggplot(df) + geom_tile(aes(x=x,y=y, fill="whatever"))
plotly::ggplotly(p1)

p2 <- ggplot(df) + geom_tile(aes(x=x,y=y))
plotly::ggplotly(p2)

Close #1562: handle geom_tile() with no fill aesthetic

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ggplotly fails to convert geom_tile element with no fill aesthetic. #1562

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ggplotly fails to convert geom_tile element with no fill aesthetic. #1562

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bwu62 commented on Jul 16, 2021

wkumler commented on Jul 21, 2021

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