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First Argument in Function.prototype.call should be optional聽#44530
Description
馃晽 Version & Regression Information
Occurs in the latest Version (4.3.2) and nightly version
馃捇 Code
Function.prototype.call combined with Optional Chaining is a nice way to only call a method if the method is defined (see this thread).
foo?.call()
馃檨 Actual behavior
Ts complains: Expected at least 1 arguments, but got 0
馃檪 Expected behavior
I expect that this works as the first argument is actually optional according to Mozilla and own observations.
Activity
MartinJohns commentedon Jun 10, 2021
Am I missing something weird here? You can do that with the
?.()operator as well.https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Optional_chaining#optional_chaining_with_function_calls
jonath92 commentedon Jun 10, 2021
I didn't know that. This is indeed much better as you don't loose IntelliSense that way. Thanks. But this is a Bug anyway (also not very important tbh) :-)
MartinJohns commentedon Jun 10, 2021
It's not explicitly mentioned, but #27028 seems to me more like it's a design decision, not a bug. Calling
.call()without athisArgrarely makes sense, and in these few cases you can just passundefinedalong.