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Declaration emit for function parameter type references incorrect type alias #12343
Description
TypeScript Version: 2.0.10 (broken since 2.0.2).
Code
export type Foo<A, B> = A | B;
export type Bar<T> = Foo<number, T>;
export const f = <T>(bar: Bar<T>) => {
return true;
};Expected behavior:
tsc --declaration bar.ts should emit the following bar.d.ts:
export declare type Foo<A, B> = A | B;
export declare type Bar<T> = Foo<number, T>;
export declare const f: <T>(bar: Bar<T>) => boolean;NB: 2.0.0 emits <T>(bar: number | T) => boolean, which is acceptable too.
Actual behavior:
export declare type Foo<A, B> = A | B;
export declare type Bar<T> = Foo<number, T>;
export declare const f: <T>(bar: Foo<T>) => boolean;
// TS2314: Generic type 'Foo' requires 2 type argument(s).
Activity
vsiao commentedon Nov 18, 2016
ah, sorry—looks like this was fixed for 2.1: #11931
vsiao commentedon Nov 18, 2016
Looks good in nightly, but still broken in 2.1.1 (RC). Mohamed Hegazy (@mhegazy) can you confirm which release the fix will be in?