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3 changes: 1 addition & 2 deletions Week_04/id_8/NOTE.md
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# 学习笔记

递推公式:
f(n) = f(n-1)+f(n-2)
分解子问题,f(n-1)和f(-2)解决了,f(n)自然解决了。


比如求 f(3),只要知道f(2)和f(1)的数值,根据递推公式,就能递推出f(3)的值