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67 changes: 67 additions & 0 deletions Week_02/id_9/LeetCode_242_9.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,67 @@
package com.github.lifelab.leetcode.problemset;

import java.util.Arrays;
import java.util.HashMap;
import java.util.Map;
import java.util.Objects;

/**
* 有效的字母异位词 @see https://leetcode-cn.com/problems/valid-anagram/
*
* @author Weichao Li (liweichao0102@gmail.com)
* @since 2019-06-16
*/
public class Solution242 {

public boolean isAnagram(String s, String t) {
if (Objects.isNull(s) || Objects.isNull(t)) {
return false;
}
if (s.length() != t.length()) {
return false;
}

char[] temp = new char[26];

for (int i = 0; i < s.length(); i++) {
temp[s.charAt(i) - 'a']++;
temp[t.charAt(i) - 'a']--;
}

for (int i = 0; i < temp.length; i++) {
if (temp[i] != 0) {
return false;
}
}
return true;
}

public boolean isAnagram1(String s, String t) {
if (Objects.isNull(s) || Objects.isNull(t)) {
return false;
}
if (s.length() != t.length()) {
return false;
}
char[] sarray = s.toCharArray();
char[] tarray = t.toCharArray();
Arrays.sort(sarray);
Arrays.sort(tarray);
return Arrays.equals(sarray, tarray);
}

public boolean isAnagram2(String s, String t) {
if (Objects.isNull(s) || Objects.isNull(t)) {
return false;
}
if (s.length() != t.length()) {
return false;
}
Map<Character, Integer> maps = new HashMap<>(t.length());
for (int i = 0; i < s.length(); i++) {
maps.compute(s.charAt(i), (k, v) -> maps.getOrDefault(k, 0) + 1);
maps.compute(t.charAt(i), (k, v) -> maps.getOrDefault(k, 0) - 1);
}
return maps.values().stream().parallel().allMatch(e -> Objects.isNull(e) | e == 0);
}
}
29 changes: 29 additions & 0 deletions Week_02/id_9/LeetCode_98_9.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,29 @@
package com.github.lifelab.leetcode.problemset;

/**
* 验证二叉搜索树 @see https://leetcode-cn.com/problems/validate-binary-search-tree/submissions/
*
* @author Weichao Li (liweichao0102@gmail.com)
* @since 2019-06-16
*/
public class Solution98 {

long temp = Long.MIN_VALUE;

public boolean isValidBST(TreeNode root) {
//terminator
if (root == null) {
return true;
}

// process
if (isValidBST(root.left)) {
if (temp < root.val) {
temp = root.val;
//drill down
return isValidBST(root.right);
}
}
return false;
}
}