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9 changes: 9 additions & 0 deletions 이니지수/15650_N과 M(2).py
Original file line number Diff line number Diff line change
@@ -0,0 +1,9 @@
import itertools

n, m = map(int, input().split())
numlist = list(range(1, n+1))
num = list(itertools.combinations(numlist ,m))
for i in num:
for j in i:
print(j, end= ' ')
print()
15 changes: 15 additions & 0 deletions 이니지수/1978_소수 찾기.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,15 @@
n = int(input())
num = map(int, input().split())

sum = 0
for i in num:
zeroNum = 0
if i == 1:
zeroNum +=1
else:
for j in range(2, int(i)):
if i % j == 0:
zeroNum+=1
if zeroNum == 0:
sum+=1
print(sum)
43 changes: 43 additions & 0 deletions 이니지수/5567_결혼식.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,43 @@
# 5567 결혼식

# 입력 값

# 6
# 5
# 1 2
# 1 3
# 3 4
# 2 3
# 4 5

import sys
from collections import deque

N = int(sys.stdin.readline())
M = int(sys.stdin.readline())

graph = [[False] * (N + 1) for _ in range(N + 1)]

for _ in range(M):
a, b = map(int, sys.stdin.readline().split())
graph[a].append(b) # a 인덱스에 b 넣기
graph[b].append(a) # b 인덱스에 a 넣기

visited = [0] * (N + 1) # false 대신 0 넣기 -> 더해야돼서!

def bfs(V):
q = deque([V])
visited[V] = 1
while q:
V = q.popleft()
for i in graph[V]:
if visited[i] == 0:
q.append(i)
visited[i] = visited[V] + 1
bfs(1)
result = 0
for i in range(2,N+1):
# 본인이거나 친구거나, 친구의 친구거나 경우의 수가 최대 3개
if 0 < visited[i] <=3:
result += 1
print(result)
38 changes: 38 additions & 0 deletions 이니지수/5567뼈대.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,38 @@
# 5567 결혼식

# 입력 값

# 6
# 5
# 1 2
# 1 3
# 3 4
# 2 3
# 4 5

import sys
from collections import deque

# N 과 M 입력 받는 방법 다름
N =
M =

graph = [[False] * (N + 1) for _ in range(N + 1)]

for _ in range(M):
a, b = map(int, sys.stdin.readline().split())
#그래프 초기 세팅 다름

visited = [0] * (N + 1) # false 대신 0

def bfs(V):
q = deque([V])
visited[V] = 1 # 숫자 덧셈에 필요
while q:
V = q.popleft()
for i in range(1, N + 1): #for문 범위 수정
if not visited[i] and graph[V][i]: # visited[i] 관련 조건 다름
q.append(i)
visited[i] = # visited[i] 구하는 방법 다름
bfs(1)
# 추가 코드